PSAD Refresher Series

Currently Playing: PSAD Refresher 81: Minimizing the Beam Depth based on Shear Strength Limitations (NSCP 2015) | RCD

Check out our Review Center: https://www.facebook.com/share/1AC24Wsb9v/?mibextid=wwXIfr SITUATION: The data of a rectangular reinforced concrete beam is given: Ultimate moment, Mu = 192 kN-m Ultimate shear at critical section, Vu = 480 kN Concrete strength, fc’ = 28 MPa Longitudinal steel, fyl = 420 MPa Transverse steel, fyv = 280 MPa Reduction factor of flexure, φ = 0.90 Reduction factor for shear, φ = 0.75 Effective concrete cover = 60 mm Architectural requirements restrict the width of the beam to 300 mm. 1. If the steel ratio is 1%, which of the following gives the required total depth (mm) of the beam. A. 500 C. 450 B. 550 D. 400 2. What is the smallest possible total depth (mm) based on shear. A. 450 C. 600 B. 500 D. 550 3. Which of the following gives the required minimum width of the beam (mm) to accommodate 4-30 mm diameter main reinforcement bars. Single layer only and bars are separate. Clear cover to 12 mm stirrups is 40 mm. A. 299 C. 325 B. 314 D. 334 Thanks for watching! Comment for questions and suggestions for future lecture in this series. Subscribe and hit the bell button to be notified for future posts. #civilengineering #boardexam #engineering #structuralanalysis #structuralengineering #CivilEngineeringLicensureExamination #PRC #PSAD #theoryofstructures #cele #strengthofmaterials #mechanicsofmaterials #staticsofrigidbodies #steeldesign #compressionmember #trusses #friction #refresher #PSADRefresher #SHET