Sequence wise lecture of ABJ sir class 11. Complete playlist of class 11 physics for Jee mains and advance . For another subject or class 12 playlist , Check on channel (if it's not there , check after few days).
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Watch Complete YouTube Lectures Distraction-Free Download the Competishun App 👉 https://play.google.com/store/apps/details?id=xyz.penpencil.competishun&pcampaignid=web_share 🌐 Login for Courses & Test Series: 👉 https://i.competishun.com/ *Popular Courses for IIT-JEE:* Pratham | Prakhar | Prakhar Integrated I | Praveen | Pragyaan C3 | Champ | CATS | ABC | PYQ Express UTS | ATS 👉 Explore all: https://competishun.com/courses/ 📞 Support: 8888-0000-21 | 7410-900-901 | 7410-900-908 --------- Topics covered in this Chapter Centre of Mass Class 11 lecture by ABJ sir IITD with timestamp: 00:00 - 08:58 Head-On Collision - Line of Motion and Line of Impact Coincide, and Line of Motion before and after the collision remains the same. ABJ Sir derives the required formulae related to head-on collisions using linear momentum conservation and the concept of coefficient of restitution. { Special Cases of Head-On Collision } 09:18 - 13:53 Special Cases of Head-On Collision: (Case 1) Same Mass - Elastic collision: For elastic collision, e=1 and according to the given condition, two blocks of the same mass will do the elastic collision. Then, their velocity will interchange after the collision. 14:03 - 15:59 Special Cases of Head-On Collision: (Case 2) Perfectly Inelastic Collision: For perfectly inelastic collision, e=0 and according to the given condition, two blocks of the masses m1 and m2 will do the perfectly inelastic collision. Then, their velocity will be the same just after the collision, meaning they will move together. 15:59 - 20:41 Special Cases of Head-On Collision: (Case 2) Collision with very heavy object: According to the given condition, two blocks of the masses m1 and m2 will do the collision (Given - m2 much greater than m1). Then, the velocity of the heavier object will remain the same before and after the collision. 21:15 - 34:35 COM Problem 1: Based on the Head-On Collision. We are solving 3 problems in one. In the first case, we have a block of 2 kg with a velocity of 10 m/s and a block of 1 kg with a velocity of 5 m/s in the same direction, and the value of the coefficient of restitution is 1. In the second case, we have a block of 1 kg with a velocity of 10 m/s and a block of 2 kg with a velocity of 1 m/s in the same direction, and the value of the coefficient of restitution is 2/3. In the third case, we have a block of 1 kg with a velocity 20 m/s and the block of 3 kg with a velocity 10 m/s in the opposite direction (towards each other), and value of coefficient of restitution is 1/3. So we have to analyze all three cases. 34:47 - 41:55 COM Problem 2: Based on the Head-On Collision. We are solving 3 problems in one. In the first case, we have a block of 2 kg with the velocity 20 m/s and the block of 1 kg with the velocity 5 m/s in the opposite direction (towards each other), and value of coefficient of restitution is 3/5. So we have to analyse all three cases. In the second case, we have a block of 2 kg with the velocity 30 m/s and the block of 2 kg with the velocity 10 m/s in the opposite direction(toward each other), and value of coefficient of restitution is 1/2. In the third case, we have a block of 3 kg with the velocity 17 m/s and the block of 4 kg with the velocity 19 m/s in the same direction, and value of coefficient of restitution is 2/7. So we have to analyse all three cases. 42:22 - 47:49 COM Problem 3: Based on the collision. In this problem, we have a plank and a ball of mass 2 kg moving toward plank with a velocity of 5 m/s and velocity of plank is 3m/s (Follow Diagram). Find their velocities just after the collision. 48:09 - 01:00:11 COM Problem 4: Based on the collision. In this problem, we have a horizontal smooth fixed ring of radius 5m and there are two beads A and B of mass 17 and 19 g respectively (Follow Diagram). At time t=0, they are colliding, so we have to find the time when next collision will take place. 01:00:29 - 01:15:39 Oblique Collision (2D Collision): Line of Motion and Line of Impact will be different, and Line of Motion after the collision will change. ABJ Sir derives the required formulae related to oblique collisions using linear momentum conservation and the concept of coefficient of restitution. 01:16:28 COM Problem 5: Based on the Oblique Collision. In this problem, we have a particle doing projectile motion on a surface with the coefficient of restitution e. We have to analyse the projectile motion of ball.