Sequence wise lecture of ABJ sir class 11. Complete playlist of class 11 physics for Jee mains and advance . For another subject or class 12 playlist , Check on channel (if it's not there , check after few days).
Curated by: Athera (178 videos)
Watch Complete YouTube Lectures Distraction-Free Download the Competishun App 👉 https://play.google.com/store/apps/details?id=xyz.penpencil.competishun&pcampaignid=web_share 🌐 Login for Courses & Test Series: 👉 https://i.competishun.com/ *Popular Courses for IIT-JEE:* Pratham | Prakhar | Prakhar Integrated I | Praveen | Pragyaan C3 | Champ | CATS | ABC | PYQ Express UTS | ATS 👉 Explore all: https://competishun.com/courses/ 📞 Support: 8888-0000-21 | 7410-900-901 | 7410-900-908 Topics covered in this Chapter Centre of Mass Class 11 lecture by ABJ sir IITD with timestamp: 00:00 - 07:48 Centre of Mass of Uniform Half Disc: The Centre of mass distribution in space is where the distributed mass's weighted relative location amounts to zero. In the case of a single rigid body, the Centre of mass is set about the body, and it would be located at the centroid if the body has uniform density. The Centre of mass may not correspond to the location of any particular system member in the case of a distribution of different bodies, such as the planets of the Solar System. ABJ Sir derives the Formula of COM of the uniform half Disc of mass M and Radius R. 07:48 - 09:02 Centre of Mass of Uniform Quarter Disc: ABJ Sir derives the Formula of COM of the uniform Quarter Disc of mass M and Radius R. 09:16 - 20:05 Centre of Mass of Uniform Hollow Hemi-Sphere: ABJ Sir derives the Formula of COM of the Uniform Hollow Hemi-Sphere of mass M and Radius R. 20:26 - 29:54 Centre of Mass of Uniform Solid Hemi-Sphere: The Centre of mass distribution in space is where the distributed mass's weighted relative location amounts to zero. In the case of a single rigid body, the Centre of mass is set about the body, and it would be located at the centroid if the body has uniform density. ABJ Sir derives the Formula of COM of the Uniform Solid Hemi-Sphere of mass M and Radius R. 29:56 - 38:52 Centre of Mass of Uniform Solid Cone: The Centre of mass distribution in space is where the distributed mass's weighted relative location amounts to zero. In the case of a single rigid body, the Centre of mass is set about the body, and it would be located at the centroid if the body has uniform density. ABJ Sir derives the Formula of COM of the Uniform Solid Cone of mass M, Radius of Base R and Height H. 38:52 - 49:44 Centre of Mass of Uniform Hollow Cone: ABJ Sir derives the Formula of COM of the Uniform Hollow Cone of mass M, Radius of Base R and Slant Height l. We have to remember these Formulas to quick problem-solving. 49:55 - 56:16 Centre of mass of an object with Cavity: To solve these types of problems, take a negative mass at the place of a Cavity with the same size and same shape of the cavity, and using the formula of COM of two bodies, we can find out the COM of the object with the cavity. 56:22 - 01:00:28 COM Problem 1: Based on the COM Of the Object with the Cavity. In this Problem, We have a Disc of Radius R and there is a cavity of radius R/2 as given in the diagram. We have to find the position of COM of this system. 01:00:28 - 01:07:33 COM Problem 2: Based on the COM Of the Object with the Cavity. In this Problem, We have a Disc of Radius R and there is two cavities of radius R/2 as given in the diagram. We have to find the position of COM of this system. 01:08:08 - 01:12:40 COM Problem 3: Based on the COM Of the Object with the Cavity. In this Problem, We have a Uniform Semi Circular Disc of Radius R and there is a circular cavity of radius R/4 as given in the diagram. We have to find the position of COM of this system. 01:12:45 - 01:21:21 Motion of Centre of Mass (COM): A system consists of n number of particles having masses m1, m2, m3 ,.... and total mass of the system is M. ABJ Sir explain Motion of COM of a system using an example. ABJ Sir also derives the formula of velocity of the COM of this system and Total momentum of the system. 01:21:30 - 01:25:16 COM Problem 3: Based on the Motion of COM. In this Problem, there are two blocks of mass 2kg and 3 kg and their velocities are 5 m/s. (Diagram of the situation is given) We have to find the velocity of COM of this system. 01:25:16 - 01:36:32 Motion of Centre of Mass (COM): Using the formula of Velocity of COM, we can also write the formula of Acceleration of the COM of this system. ABJ Sir explain this term, using an example.