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Curated by: Khan Academy India - English (21 videos)
We pick things up from where we left in the previous video and tackle a really hairy constraint in this one. We find the number of ways to rearrange letters of a word when two given letters are always three letters apart. For this we break down the constraint into its components - easier problems that are independently solvable. We then combine the three to get to the final answer. Courses on Khan Academy are always 100% free. Start practicing—and saving your progress—now! https://www.khanacademy.org/math/ncert-class-11/xea4762213f311c5e:permutations-and-combinations-ncert-new/xea4762213f311c5e:untitled-900/e/permutations_1) Timestamps: 00:00 A quick recap of previous parts of the problem 01:06 Understanding the constraint 02:19 Coming up with an approach to solve the problem 02:46 Applying the approach - removing P and I 03:38 Arranging the remaining letters 04:16 Dealing with a particular arrangement 05:30 Finding number of ways to create space for P and I 06:53 Putting it all together 07:54 Final answer - bringing back the solutions of individual parts Khan Academy India is a nonprofit organization with the mission of providing a free, world-class education for anyone, anywhere. We have videos and exercises that have been translated into multiple Indian languages, and 15 million people around the globe learn on Khan Academy every month. Support Us: https://india.khanacademy.org/donate Created by Ashish Gupta